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why does initialization narrow type? #8513

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@zpdDG4gta8XKpMCd

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@zpdDG4gta8XKpMCd
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nightly build

"compilerOptions": {
        "module": "amd",
        "moduleResolution": "classic",
        "noEmitOnError": true,
        "allowUnreachableCode": false,
        "allowUnusedLabels": false,
        "outDir": "./built",
        "noResolve": true,
        "noImplicitAny": true,
        "noImplicitReturns": true,
        "forceConsistentCasingInFileNames": true,
        "noFallthroughCasesInSwitch": true,
        "target": "es5"
        // "strictNullChecks": true
    }
export type Optional<a> = Some<a> | None;

export interface None { readonly none: string; }
export interface Some<a> { readonly some: a; }

export const none : None = { none: '' };

export function isSome<a>(value: Optional<a>): value is Some<a> {
    return 'some' in value;
}

export function fn<r>(): void {
    let result: Optional<r> = none;
    isSome(result)
        ? result.some
        : undefined
}

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