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Inference doesn't work with union types #2264

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@zpdDG4gta8XKpMCd
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I don't understand what is wrong with the following piece of code. It's a very basic scenario that I wish I could have since now union types are here. Please let me know what I am doing wrong:

interface Y { 'i am a very certain type': Y }
var y : Y = <Y> undefined;
function destructure<a, r>(
    something: a | Y,
    haveValue: (value: a) => r,
    haveY: (value: Y) => r
) : r {
    return something === y ? haveY(y) : haveValue(<a> something);
}

var value = Math.random() > 0.5 ? 'hey!' : <Y> undefined;

console.log(destructure(value, text => 'string', y => 'other one')); // <-- complete mess and failure

At playground: http://www.typescriptlang.org/Playground#src=interface%20Y%20%7B%20'i%20am%20a%20very%20certain%20type'%3A%20Y%20%7D%0Avar%20y%20%3A%20Y%20%3D%20%3CY%3E%20undefined%3B%0Afunction%20destructure%3Ca%2C%20r%3E(%0A%09something%3A%20a%20%7C%20Y%2C%0A%09haveValue%3A%20(value%3A%20a)%20%3D%3E%20r%2C%0A%09haveY%3A%20(value%3A%20Y)%20%3D%3E%20r%0A)%20%3A%20r%20%7B%0A%09return%20something%20%3D%3D%3D%20y%20%3F%20haveY(y)%20%3A%20haveValue(%3Ca%3E%20something)%3B%0A%7D%0A%0Avar%20value%20%3D%20Math.random()%20%3E%200.5%20%3F%20'hey!'%20%3A%20%3CY%3E%20undefined%3B%0A%0Aconsole.log(destructure(value%2C%20text%20%3D%3E%20'string'%2C%20b%20%3D%3E%20'other%20one'))%3B%20%2F%2F%20%3C--%20complete%20mess%20and%20failure%0A

Related question at StackOverflow: http://stackoverflow.com/questions/28931221/whats-the-use-of-union-types-in-typescript

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