Skip to content

Navigation Menu

Sign in
Appearance settings

Search code, repositories, users, issues, pull requests...

Provide feedback

We read every piece of feedback, and take your input very seriously.

Saved searches

Use saved searches to filter your results more quickly

Appearance settings

Latest commit

 

History

History
History
127 lines (108 loc) · 3.86 KB

File metadata and controls

127 lines (108 loc) · 3.86 KB
Copy raw file
Download raw file
Open symbols panel
Edit and raw actions
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
"""
N-Sum
Given an array of integers, find all unique n-tuples that sum to a target
value. Supports custom sum, comparison, and equality closures for advanced
use cases with non-integer elements.
Reference: https://leetcode.com/problems/4sum/
Complexity:
Time: O(n^(k-1)) where k is the tuple size
Space: O(n^(k-1)) for storing results
"""
from __future__ import annotations
from collections.abc import Callable
from typing import Any
def n_sum(
n: int,
nums: list[Any],
target: Any,
**kv: Callable[..., Any],
) -> list[list[Any]]:
"""Find all unique n-tuples in nums that sum to target.
Args:
n: Size of each tuple to find.
nums: List of elements to search.
target: Desired sum for each n-tuple.
**kv: Optional closures:
sum_closure(a, b) - returns sum of two elements.
compare_closure(num, target) - returns -1, 0, or 1.
same_closure(a, b) - returns True if elements are equal.
Returns:
Sorted list of unique n-tuples (as lists) that sum to target.
Examples:
>>> n_sum(3, [-1, 0, 1, 2, -1, -4], 0)
[[-1, -1, 2], [-1, 0, 1]]
"""
def _sum_closure_default(a: Any, b: Any) -> Any:
return a + b
def _compare_closure_default(num: Any, target: Any) -> int:
if num < target:
return -1
elif num > target:
return 1
else:
return 0
def _same_closure_default(a: Any, b: Any) -> bool:
return a == b
def _n_sum_inner(n: int, nums: list[Any], target: Any) -> list[list[Any]]:
if n == 2:
results = _two_sum(nums, target)
else:
results = []
prev_num = None
for index, num in enumerate(nums):
if prev_num is not None and same_closure(prev_num, num):
continue
prev_num = num
n_minus1_results = _n_sum_inner(
n - 1,
nums[index + 1 :],
target - num,
)
n_minus1_results = _append_elem_to_each_list(num, n_minus1_results)
results += n_minus1_results
return _union(results)
def _two_sum(nums: list[Any], target: Any) -> list[list[Any]]:
nums.sort()
left = 0
right = len(nums) - 1
results = []
while left < right:
current_sum = sum_closure(nums[left], nums[right])
flag = compare_closure(current_sum, target)
if flag == -1:
left += 1
elif flag == 1:
right -= 1
else:
results.append(sorted([nums[left], nums[right]]))
left += 1
right -= 1
while left < len(nums) and same_closure(nums[left - 1], nums[left]):
left += 1
while right >= 0 and same_closure(nums[right], nums[right + 1]):
right -= 1
return results
def _append_elem_to_each_list(
elem: Any, container: list[list[Any]]
) -> list[list[Any]]:
results = []
for elems in container:
elems.append(elem)
results.append(sorted(elems))
return results
def _union(
duplicate_results: list[list[Any]],
) -> list[list[Any]]:
results = []
if len(duplicate_results) != 0:
duplicate_results.sort()
results.append(duplicate_results[0])
for result in duplicate_results[1:]:
if results[-1] != result:
results.append(result)
return results
sum_closure = kv.get("sum_closure", _sum_closure_default)
same_closure = kv.get("same_closure", _same_closure_default)
compare_closure = kv.get("compare_closure", _compare_closure_default)
nums.sort()
return _n_sum_inner(n, nums, target)
Morty Proxy This is a proxified and sanitized view of the page, visit original site.