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print_exception.py

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 parse-bytecode

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print_exception.py

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import _io as io # uPy does not have io module builtin

import sys

if hasattr(sys, 'print_exception'):

print_exception = sys.print_exception

else:

import traceback

print_exception = lambda e, f: traceback.print_exception(None, e, sys.exc_info()[2], file=f)

def print_exc(e):

buf = io.StringIO()

print_exception(e, buf)

s = buf.getvalue()

for l in s.split("\n"):

# uPy on pyboard prints <stdin> as file, so remove filename.

if l.startswith(" File "):

l = l.split('"')

print(l[0], l[2])

# uPy and CPy tracebacks differ in that CPy prints a source line for

# each traceback entry. In this case, we know that offending line

# has 4-space indent, so filter it out.

elif not l.startswith(" "):

print(l)

# basic exception message

try:

1/0

except Exception as e:

print('caught')

print_exc(e)

# exception message with more than 1 source-code line

def f():

g()

def g():

2/0

try:

f()

except Exception as e:

print('caught')

print_exc(e)