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# stress test for the heap by allocating lots of objects within threads

# allocates about 5mb on the heap

#

# MIT license; Copyright (c) 2016 Damien P. George on behalf of Pycom Ltd

try:

import utime as time

except ImportError:

import time

import _thread

def last(l):

return l[-1]

def thread_entry(n):

# allocate a bytearray and fill it

data = bytearray(i for i in range(256))

# run a loop which allocates a small list and uses it each iteration

lst = 8 * [0]

sum = 0

for i in range(n):

sum += last(lst)

lst = [0, 0, 0, 0, 0, 0, 0, i + 1]

# check that the bytearray still has the right data

for i, b in enumerate(data):

assert i == b

# print the result of the loop and indicate we are finished

with lock:

print(sum, lst[-1])

global n_finished

n_finished += 1

lock = _thread.allocate_lock()

n_thread = 10

n_finished = 0

# spawn threads

for i in range(n_thread):

_thread.start_new_thread(thread_entry, (10000,))

# wait for threads to finish

while n_finished < n_thread:

time.sleep(1)