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/*
* 把一个数组最开始的若干元素搬到数组的末尾,我们称之为数组的旋转
* 输入一个非递减排序的数组的一个旋转,输出旋转数组的最小元素
* 例如数组{3,4,5,1,2}为{1,2,3,4,5}的一个旋转,该数组的最小值为1
* NOTE:给出的所有元素都大于0,若数组大小为0,请返回0
* 其实就是找出数组中最小值的遍体
*/
//暴力遍历法,数据量少的时候还可以,简单粗暴
class solution{
public:
int minNumberInRotateArray(vector<int> rotateArray){
if(rotateArray.size()==0)
return 0;
int minimum=rotateArray[0];
for(int i=1;i<rotateArray.size();i++)
if(minimum>rotateArray[i])
minimum=rotateArray[i];
return minimum;
}
}
//二分法
class solution{
public:
int minNumberInRotateArray(vector<int> rotateArray){
if(rotateArray.size()==0)
return 0;
int head=0,tail=rotateArray.size()-1,mid=(head+tail)/2;
//没有旋转的情况,或者说旋转后和原数组一样的情况
if(rotateArray[head]<rotateArray[tail])
return rotateArray[head];
while(rotateArray[head]>=rotateArray[tail]){
if(tail-head==1){
mid=tail;
break;
}
if(rotateArray[mid]>=rotateArray[head])
head=mid;
else if(rotateArray[mid]<rotateArray[tail])
tail=mid;
mid=(head+tail)/2;
}
return rotateArray[mid];
}
}
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