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/*Given two arrays, write a function to compute their intersection.
*
*Example:
*Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2].
*
*Note:
*Each element in the result should appear as many times as it shows in both arrays.
*The result can be in any order.
*Follow up:
*What if the given array is already sorted? How would you optimize your algorithm?
*What if nums1's size is small compared to nums2's size? Which algorithm is better?
*What if elements of nums2 are stored on disk, and the memory is limited such that you cannot load all elements into the memory at once?
*/
class Solution {
public:
vector<int> intersect(vector<int>& nums1, vector<int>& nums2) {
vector<int> ret;
if(nums1.empty()||nums2.empty())
return ret;
sort(nums1.begin(),nums1.end());
sort(nums2.begin(),nums2.end());
vector<int>::iterator it1=nums1.begin();
vector<int>::iterator it2=nums2.begin();
while(it1!=nums1.end()&&it2!=nums2.end()){
if(*it1==*it2){
ret.push_back(*it1);
it1++;
it2++;
}
else if(*it1>*it2){
it2++;
}
else if(*it1<*it2){
it1++;
}
}
return ret;
}
};
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