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//
// Solution127.cpp
// Algorithm
//
// Created by Pancf on 2020/12/19.
// Copyright © 2020 Pancf. All rights reserved.
//
#include "Solution127.hpp"
#include <unordered_set>
int Solution127::ladderLength(std::string beginWord, std::string endWord, std::vector<std::string> &wordList)
{
// BFS
std::unordered_set<std::string> wordSet(wordList.begin(), wordList.end());
std::unordered_set<std::string> head, tail, *headPtr, *tailPtr;
if (wordSet.find(endWord) == wordSet.end()) return 0;
head.insert(beginWord);
tail.insert(endWord);
int res = 2;
while (!head.empty() && !tail.empty()) {
// ensure we always traversing smaller set
if (head.size() < tail.size()) {
headPtr = &head;
tailPtr = &tail;
} else {
headPtr = &tail;
tailPtr = &head;
}
std::unordered_set<std::string> temp;
for (auto it = headPtr->begin(); it != headPtr->end(); ++it) { // all neighbors
auto word = *it;
for (int i = 0; i < word.size(); ++i) {
auto ch = word[i];
for (int k = 0; k < 26; k++) { // change one char each iter and find whether can transform
word[i] = 'a' + k;
if (tailPtr->find(word) != tailPtr->end()) {
return res;
}
if (wordSet.find(word) != wordSet.end()) { // if can transform, this word is the neighbor
temp.insert(word);
wordSet.erase(word);
}
}
word[i] = ch;
}
}
res++;
headPtr->swap(temp);
}
return 0;
}
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