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package com.others;
import java.math.BigInteger;
/**
* We may calculate power with loops, but what if the index is too large ?
* FastPower aims to calculate quickly in this circumstances with time complexity O(log k),
* where k is the index.
*
*/
public class FastPower {
public static BigInteger calculate(BigInteger n, BigInteger k, BigInteger mod) {
BigInteger ans = BigInteger.ONE;
while (!k.equals(BigInteger.ZERO)) {
int odd = k.mod(BigInteger.valueOf(2)).compareTo(BigInteger.ZERO);
if (odd > 0) {
ans = ans.multiply(n).mod(mod);
}
k = k.divide(BigInteger.valueOf(2));
n = n.multiply(n).mod(mod);
}
return ans.mod(mod);
}
public static long calculate(long n, long k, long mod) {
long ans = 1;
while (k != 0) {
if (k % 2 == 1) {
ans = (ans * n) % mod;
}
k >>= 1;
n = (n * n) % mod;
}
return ans % mod;
}
}
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