Enumerable.ElementAt<TSource> Method (IEnumerable<TSource>, Int32)
Returns the element at a specified index in a sequence.
Assembly: System.Core (in System.Core.dll)
Parameters
- source
-
Type:
System.Collections.Generic.IEnumerable<TSource>
An IEnumerable<T> to return an element from.
- index
-
Type:
System.Int32
The zero-based index of the element to retrieve.
Return Value
Type: TSourceThe element at the specified position in the source sequence.
Type Parameters
- TSource
The type of the elements of source.
| Exception | Condition |
|---|---|
| ArgumentNullException | source is null. |
| ArgumentOutOfRangeException | index is less than 0 or greater than or equal to the number of elements in source. |
If the type of source implements IList<T>, that implementation is used to obtain the element at the specified index. Otherwise, this method obtains the specified element.
This method throws an exception if index is out of range. To instead return a default value when the specified index is out of range, use the ElementAtOrDefault<TSource> method.
The following code example demonstrates how to use ElementAt<TSource> to return an element at a specific position.
string[] names = { "Hartono, Tommy", "Adams, Terry", "Andersen, Henriette Thaulow", "Hedlund, Magnus", "Ito, Shu" }; Random random = new Random(DateTime.Now.Millisecond); string name = names.ElementAt(random.Next(0, names.Length)); Console.WriteLine("The name chosen at random is '{0}'.", name); /* This code produces the following sample output: The name chosen at random is 'Ito, Shu'. */
Available since 8
.NET Framework
Available since 3.5
Portable Class Library
Supported in: portable .NET platforms
Silverlight
Available since 2.0
Windows Phone Silverlight
Available since 7.0
Windows Phone
Available since 8.1