Extracting Elements from Array

Question

From a given array, extract all the elements which are greater than 'm' and less than 'n'. Note: 'm' and 'n' are integer values provided as input.

Input format:

A list of integers on line one

Integer 'm' on line two

Integer 'n' on line three

Output format:

1-D array containing integers greater than 'm' and smaller than 'n'.

Sample input:

[ 1, 5, 9, 12, 15, 7, 12, 9 ] (array)

6 (m)

12 (n)

Sample output:

[ 9 7 9 ]

Sample input:

[ 1, 5, 9, 12, 15, 7, 12, 9 ]

12

6

Sample output:

[ ]

Answer 1

This should do the job.

take 2 input in int format. then iterate over the given array and put a if condition like below :-

arr  = [ 1, 5, 9, 12, 15, 7, 12, 9 ]

max = int(input("Max : "))

min = int(input("Min : "))

output = []
for a in range(len(arr)):
    if arr[a] > max and arr[a] < min :
        print(arr[a])
        output.append(arr[a])

Answer 2

Make the array (not a list!)

In [857]: x = np.array([ 1, 5, 9, 12, 15, 7, 12, 9 ])

test against the lower bound:

In [858]: x>6
Out[858]: array([False, False,  True,  True,  True,  True,  True,  True])

and the upper:

In [859]: x<12
Out[859]: array([ True,  True,  True, False, False,  True, False,  True])

combine them:

In [860]: (x>6)&(x<12)
Out[860]: array([False, False,  True, False, False,  True, False,  True])

Use that as a boolean mask to select elements from x:

In [861]: mask = (x>6)&(x<12)
In [862]: x[mask]
Out[862]: array([9, 7, 9])