Checking Pangram in Python

Question

I am trying to use .pop to check the pangram and have the following code but get the error "'str' object has no attribute 'pop'". I am new to programming. Please help.

import string

def ispangram(str1, alphabet=string.ascii_lowercase):
    for x in str1:
        if x in alphabet:
            alphabet.pop[0]
        else:
            pass
    return len(alphabet)==0

Answer 1

One approach is to use sets:

import string 

def check(s):
    """ 
    Return True if string s is Panagram
    """
    alphabet=string.ascii_lowercase
    return set(alphabet) - set(s.lower()) == set([])

PS: If you want to see what attributes/methods of an object just use dir(<object>)

Answer 2

List and dictionary objects only have popmethod.You are trying to delete the character in the 0th index of string. Thus you can try this :

def ispangram(str1, alphabet=string.ascii_lowercase):
    for x in str1:
        if x in alphabet:
            alphabet = alphabet[1:]
        else:
            pass
    return len(alphabet)==0

output

print (ispangram("The quick brown fox jump over the lazy dog", "s"))

False