I have two lists in R of identical length and would like to combine them into a data frame with the total number of rows in the resulting data frame equivalent to the length of the two lists (in other words, each list is a column). When I tried using c(list1, list2) the two lists were appended together and when I used cbind(list1, list2) the total number of observations was almost double the original length.
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1 Answer
Try
do.call(rbind.data.frame, Map('c', list1, list2))
data
list1 <- as.list(1:5)
list2 <- as.list(6:10)
answered Jun 11, 2015 at 4:22
4 Comments
g.humpkins
I used the last piece of code and received an error saying "Error in data.frame(Col1 = unlist(lat_long_zip_key), Col2 = unlist(listing_id)) : arguments imply differing number of rows: 57246, 57258" However, when I run the length of the two lists,
length(listing_id) [1] 57258 and length(lat_long_zip_key) [1] 57258 they appear to have the same length. Any suggestions?akrun
@g.humpkins I was assuming that your list elements have the same length, but if that is not the case, the
unlist in both list will return different length. Can you show a small reproducible example that shows the error?g.humpkins
Ah, I was able to get it to work with your first code snippet, thanks! Do you have any clue why when I test the length of the lists, they are equivalent, but when I used the
unlist code they were not?akrun
@g.humpkins You are looking at the
length of the entire list and from your description, both lists have the same length. But, what if some elements inside that list different in length or nrow etc? Try to check sapply(listing_id, length) or lengths(listiing_id) (in R 3.2.0)