fnmatch --- Unix 檔案名稱模式比對¶

原始碼：Lib/fnmatch.py

This module provides support for Unix shell-style wildcards, which are not the same as regular expressions (which are documented in the re module). The special characters used in shell-style wildcards are:

For a literal match, wrap the meta-characters in brackets. For example, '[?]' matches the character '?'.

Note that the filename separator ('/' on Unix) is not special to this module. See module glob for pathname expansion (glob uses filter() to match pathname segments). Similarly, filenames starting with a period are not special for this module, and are matched by the * and ? patterns.

Unless stated otherwise, "filename string" and "pattern string" either refer to str or ISO-8859-1 encoded bytes objects. Note that the functions documented below do not allow to mix a bytes pattern with a str filename, and vice-versa.

Finally, note that functools.lru_cache() with a maxsize of 32768 is used to cache the (typed) compiled regex patterns in the following functions: fnmatch(), fnmatchcase(), filter().

fnmatch.fnmatch(name, pat)¶

Test whether the filename string name matches the pattern string pat, returning True or False. Both parameters are case-normalized using os.path.normcase(). fnmatchcase() can be used to perform a case-sensitive comparison, regardless of whether that's standard for the operating system.

This example will print all file names in the current directory with the extension .txt:

import fnmatch
import os

for file in os.listdir('.'):
    if fnmatch.fnmatch(file, '*.txt'):
        print(file)

fnmatch.fnmatchcase(name, pat)¶

Test whether the filename string name matches the pattern string pat, returning True or False; the comparison is case-sensitive and does not apply os.path.normcase().

fnmatch.filter(names, pat)¶

Construct a list from those elements of the iterable of filename strings names that match the pattern string pat. It is the same as [n for n in names if fnmatch(n, pat)], but implemented more efficiently.

fnmatch.translate(pat)¶

Return the shell-style pattern pat converted to a regular expression for using with re.match(). The pattern is expected to be a str.

範例：

>>> import fnmatch, re
>>>
>>> regex = fnmatch.translate('*.txt')
>>> regex
'(?s:.*\\.txt)\\Z'
>>> reobj = re.compile(regex)
>>> reobj.match('foobar.txt')
<re.Match object; span=(0, 10), match='foobar.txt'>