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package MethodOverloading;

public class NullTest1 {

/*

* If more than one member method is both accessible and applicable to a method invocation,

* it is necessary to choose one to provide the descriptor for the run-time method dispatch.

*

* The Java programming language uses the rule that the most specific method is chosen.

* */

public static void method(Object obj){

System.out.println("method with param type - Object");

}

public static void method(String obj){

System.out.println("method with param type - String");

}

// public static void method(StringBuffer strBuf){

// System.out.println("method with param type - StringBuffer");

// }

/*

* Why is the compiler not able to pick 'the most specific' here - because both "String" and "StringBuffer" are are sub-classes.

of the Object class, but without being in the same inheritance hierarchy. For finding

'the most specific' method, the compiler needs to find a method having the parameter type,

which is a sub-class of the parameter types of all other overloaded methods.

* */

public static void main(String [] args){

method(null);

}

}