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Implement numpy's triu and tril methods #1323

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@geetmankar

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@geetmankar
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Hi, I want to propose an implementation of numpy.triu and numpy.tril methods (link here) for arrays that are atleast 2 dimensions.

import numpy as np

np.triu([[1,2,3],[4,5,6],[7,8,9],[10,11,12]], k=0)

returns:

array([[ 1,  2,  3],
       [ 0,  5,  6],
       [ 0,  0,  9],
       [ 0,  0,  0]])

and

np.triu([[1,2,3],[4,5,6],[7,8,9],[10,11,12]], k=1)

returns:

array([[ 0,  2,  3],
       [ 0,  0,  6],
       [ 0,  0,  0],
       [ 0,  0,  0]])

and

np.triu([[1,2,3],[4,5,6],[7,8,9],[10,11,12]], k=-1)

returns:

array([[ 1,  2,  3],
       [ 4,  5,  6],
       [ 0,  8,  9],
       [ 0,  0, 12]])

I implemented a basic version of np.triu and np.tril for 2D owned float square ndarrays for personal use, however I did not write it to support negative values of k.

pub trait Tri {
    fn triu(&self, k: usize) -> Self;
    fn tril(&self, k: usize) -> Self;
}

impl Tri for ArrayBase<OwnedRepr<f64>, Ix2> {
    fn triu(&self, k: usize) -> Self {
        let cols = self.len_of(Axis(1));
        let copied_arr = self.clone();

        let mut result_arr = Array2::<f64>::zeros((cols, cols).f());

        for (i, row) in copied_arr.axis_iter(Axis(0)).enumerate() {
            let slice_main = (i as usize + k)..self.len_of(Axis(0));
            row.to_owned()
                .slice(s![slice_main.clone()])
                .assign_to(result_arr.slice_mut(s![i, slice_main.clone()]));
        }

        return result_arr;
    }

   fn tril(&self, k: usize) -> Self {
        return self.clone().t().to_owned().triu(k).t().to_owned();
    }
}
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