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Code sample:
def outer(x):
return [lambda: x for x in range(x)]
print([f() for f in outer(2)])On 3.11, this produces [1, 1] as expected.
But on current main, I get:
>>> [f() for f in outer(2)]
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 2, in outer
TypeError: 'cell' object cannot be interpreted as an integer
Almost certainly due to PEP 709 / #101441, cc @carljm.
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