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>>> a = ['a', 'b', 'c', 'd', 'e']

>>> for index, item in enumerate(a): print index, item # enumerate function will generate an index for the item + item it self.

...

0 a

1 b

2 c

3 d

4 e

#convert a list to string:

list1 = ['1', '2', '3']

str1 = ''.join(list1)

Or if the list is of integers, convert the elements before joining them.

list1 = [1, 2, 3]

str1 = ''.join(str(e) for e in list1)

#FIND method

str.find(str2, beg=0 end=len(string))

Parameters

str2 -- This specifies the string to be searched.

beg -- This is the starting index, by default its 0.

end -- This is the ending index, by default its equal to the lenght of the string.

Return Value

This method returns index if found and -1 otherwise.

str1 = "this is string example....wow!!!";

str2 = "exam";

# find function will print the position for the first character of the string if it's found!

print str1.find(str2);

print str1.find(str2, 10);

print str1.find(str2, 40);

#15

#15

#-1

#2D LIST PYTHON

# Creates a list containing 5 lists initialized to 0

Matrix = [[0 for x in range(5)] for x in range(5)]

You can now add items to the list:

Matrix[0][0] = 1

Matrix[4][0] = 5

print Matrix[0][0] # prints 1

print Matrix[4][0] # prints 5

if you have a simple two-dimensional list like this:

A = [[1,2,3,4],

[5,6,7,8]]

then you can extract a column like this:

def column(matrix, i):

return [row[i] for row in matrix]

Extracting the second column (index 1):

>>> column(A, 1)

[2, 6]

Or alternatively, simply:

>>> [row[1] for row in A]

[2, 6]