FilesExpand file tree

 master

/

MaximumSubarray.java

Copy path

BlameMore file actions

BlameMore file actions

Latest commit

 

History

History

History

29 lines (28 loc) · 713 Bytes

 master

/

MaximumSubarray.java

Top

File metadata and controls

• Code
• Blame

29 lines (28 loc) · 713 Bytes

Raw

Copy raw file

Download raw file

Open symbols panel

Edit and raw actions

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

16

17

18

19

20

21

22

23

24

25

26

27

28

29

/**

* Find the contiguous subarray within an array (containing at least one number)

* which has the largest sum.

*

* For example, given the array [−2,1,−3,4,−1,2,1,−5,4], the contiguous subarray

* [4,−1,2,1] has the largest sum = 6.

*

* click to show more practice.

*

* More practice: If you have figured out the O(n) solution, try coding another

* solution using the divide and conquer approach, which is more subtle.

*/

public class MaximumSubarray {

public int maxSubArray(int[] A) {

int max = Integer.MIN_VALUE;

int sum = 0;

for (int i = 0; i < A.length; i++) {

sum += A[i];

if (sum > max) {

max = sum;

}

if (sum < 0) {

sum = 0;

}

}

return max;

}

}