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Commit 310929e

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nature1995nature1995
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Update to 016
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‎Python3/007_Reverse_Integer.py

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#!usr/bin/env python
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# -*- coding:utf-8 -*-
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'''
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Reverse digits of an integer.
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Example1: x = 123, return 321
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Example2: x = -123, return -321
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Here are some good questions to ask before coding. Bonus points for you if you have already thought through this!
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If the integer's last digit is 0, what should the output be? ie, cases such as 10, 100.
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Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. How should you handle such cases?
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For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.
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'''
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class Solution(object):
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def reverse(self, x):
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"""
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:type x: int
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:rtype: int
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"""
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# Consider positive and negative situation
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flag = 0
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if x < 0:
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flag = -1
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if x > 0:
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flag = 1
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x *= flag
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result = 0
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while x:
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result = result * 10 + x % 10
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x //= 10
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if result > 2 ** 32 - 1: #2的32次方
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return 0
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else:
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return result*flag
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if __name__ == "__main__":
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assert Solution().reverse(654300) == 3456
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assert Solution().reverse(-321) == -123
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assert Solution().reverse(21474836470) == 0
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‎Python3/009_Palindrome_Number.py

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#!usr/bin/env python
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# -*- coding:utf-8 -*-
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'''
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Determine whether an integer is a palindrome. Do this without extra space.
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Could negative integers be palindromes? (ie, -1)
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If you are thinking of converting the integer to string, note the restriction of using extra space.
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You could also try reversing an integer. However, if you have solved the problem "Reverse Integer", you know that the reversed integer might overflow. How would you handle such case?
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There is a more generic way of solving this problem.
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'''
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class Solution(object):
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def isPalindrome(self, x):
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"""
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:type x: int
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:rtype: bool
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"""
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if x < 0:
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return False
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div = 1
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while x / div >=10:
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div *= 10
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while x > 0:
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l = x // div
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r = x % 10
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if l != r:
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return False
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x %= div
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x //= 10
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div /= 100
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return True
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if __name__ == "__main__":
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assert Solution().isPalindrome(123) == False
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assert Solution().isPalindrome(12321) == True
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assert Solution().isPalindrome(-121) == False
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‎Python3/011_Container_With_Most_Water.py

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#!usr/bin/env python
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# -*- coding:utf-8 -*-
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class Solution(object):
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def maxArea(self, height):
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"""
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:type height: List[int]
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:rtype: int
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"""
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if not height:
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return 0
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left = 0
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right = len(height) - 1
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result = 0
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while left < right:
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if height[left] < height[right]:
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area = height[left] * (right - left)
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result = max(result, area)
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left += 1
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else:
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area = height[right] * (right - left)
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result = max(result, area)
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right -= 1
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return result
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if __name__ == "__main__":
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assert Solution().maxArea([1, 1]) == 1
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‎Python3/012_Integer_to_Roman.py

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#!usr/bin/env python
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# -*- coding:utf-8 -*-
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‎Python3/013_Roman_to_Integer.py

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#!usr/bin/env python
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# -*- coding:utf-8 -*-
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‎Python3/014_Longest_Common_Prefix.py

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#!usr/bin/env python
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# -*- coding:utf-8 -*-
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‎Python3/015_3Sum.py

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#!usr/bin/env python
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# -*- coding:utf-8 -*-
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‎Python3/016_3Sum_Closest.py

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#!usr/bin/env python
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# -*- coding:utf-8 -*-
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