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/**
* Given a 2D binary matrix filled with 0's and 1's, find the largest rectangle
* containing all ones and return its area.
*/
public class MaximalRectangle {
public int maximalRectangle(char[][] matrix) {
int rows = matrix.length;
if (rows == 0)
return 0;
int maxArea = 0;
int cols = matrix[0].length;
int[][] map = new int[rows][cols];
for (int j = 0; j < cols; j++) {
map[0][j] = matrix[0][j] == '0' ? 0 : 1;
}
for (int i = 1; i < rows; i++) {
for (int j = 0; j < cols; j++) {
map[i][j] = matrix[i][j] == '0' ? map[i - 1][j]
: map[i - 1][j] + 1;
}
}
int[] row = new int[cols];
for (int i = 0; i < rows; i++) {
for (int j = i; j < rows; j++) {
for (int k = 0; k < cols; k++) {
row[k] = map[j][k] - (i == 0 ? 0 : map[i - 1][k]);
}
int count = 0;
for (int k = 0; k < cols; k++) {
if (row[k] == j - i + 1) {
maxArea = Math.max(maxArea, ++count * (j - i + 1));
} else {
maxArea = Math.max(maxArea, count * (j - i + 1));
count = 0;
}
}
}
}
return maxArea;
}
}
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