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import java.util.ArrayList;
import java.util.Stack;
/**
* Given a binary tree, return the preorder traversal of its nodes' values.
*
* For example:
* Given binary tree {1,#,2,3},
* 1
* \
* 2
* /
* 3
* return [1,2,3].
*
* Note: Recursive solution is trivial, could you do it iteratively?
*
*/
public class BinaryTreePreorderTraversal {
public ArrayList<Integer> preorderTraversal(TreeNode root) {
ArrayList<Integer> ret = new ArrayList<Integer>();
if (root == null)
return ret;
Stack<TreeNode> st = new Stack<TreeNode>();
TreeNode p = root.left;
ret.add(root.val);
st.add(root);
while (!st.isEmpty()) {
while (p != null) {
ret.add(p.val);
st.add(p);
p = p.left;
}
TreeNode node = st.pop();
p = node.right;
if (p != null) {
ret.add(p.val);
st.add(p);
p = p.left;
}
}
return ret;
}
}
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