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package Algorithms;
public class FindKthNumber {
public static void main(String[] str) {
int A[] = {1,2,3,3};
int B[] = {3,3,7,8};
FindKthNumber fn = new FindKthNumber();
double ret = fn.findMedianSortedArrays(A, B);
System.out.println(ret);
}
public double findMedianSortedArrays(int A[], int B[]) {
int len = A.length + B.length;
double ret = findKth(A, 0, B, 0, 6);
return ret;
/*
if (len % 2 == 0) {
return (findKth(A, 0, B, 0, len / 2) + findKth(A, 0, B, 0, len / 2 + 1)) / 2.0 ;
} else {
return findKth(A, 0, B, 0, len / 2 + 1);
}*/
}
// find kth number of two sorted array
public static int findKth(int[] A, int A_start, int[] B, int B_start, int k){
if(A_start >= A.length)
return B[B_start + k - 1];
if(B_start >= B.length)
return A[A_start + k - 1];
if (k == 1)
return Math.min(A[A_start], B[B_start]);
int A_key = A_start + k / 2 - 1 < A.length
? A[A_start + k / 2 - 1]
: Integer.MAX_VALUE;
int B_key = B_start + k / 2 - 1 < B.length
? B[B_start + k / 2 - 1]
: Integer.MAX_VALUE;
if (A_key < B_key) {
return findKth(A, A_start + k / 2, B, B_start, k - k / 2);
} else {
return findKth(A, A_start, B, B_start + k / 2, k - k / 2);
}
}
}
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