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class Solution {
public:
int maxSubArray(int A[], int n) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
int maxsum = A[0];
int tempsum = A[0];
for (int i = 1; i < n; i++) {
if (tempsum < 0) tempsum = 0;
tempsum += A[i];
maxsum = max(maxsum, tempsum);
}
return maxsum;
}
};
//
// solution 2 : divide and conquer
//
class Solution {
public:
int maxSubArray(int A[], int n) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
return maxSubArray(A, 0, n - 1);
}
int maxSubArray(int A[], int left, int right) {
if (left > right)
return INT_MIN;
int mid = (left + right) / 2;
int lmax = maxSubArray(A, left, mid - 1);
int rmax = maxSubArray(A, mid + 1, right);
int sum = 0, mlmax = 0;
for (int i = mid - 1; i >= left; i--) {
sum += A[i];
mlmax = max(mlmax, sum);
}
sum = 0;
int mrmax = 0;
for (int i = mid + 1; i <= right; i++) {
sum += A[i];
mrmax = max(mrmax, sum);
}
return max(mlmax + A[mid] + mrmax, max(lmax, rmax));
}
};
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