hailingc
diff --git a/Collapse file
‎MergekSortedLists.java‎
Copy file name to clipboard
+92Lines changed: 92 additions & 0 deletions b/Collapse file
‎MergekSortedLists.java‎
Copy file name to clipboard
+92Lines changed: 92 additions & 0 deletions
@@ -0,0 +1,92 @@
+/*
+ Author:     King, wangjingui@outlook.com
+ Date:       Dec 17, 2014
+ Problem:    Merge k Sorted Lists
+ Difficulty: easy
+ Source:     https://oj.leetcode.com/problems/merge-k-sorted-lists/
+ Notes:
+ Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity.
+ 
+ Solution: Find the smallest list-head first using minimum-heap(lgk).
+           complexity: O(N*KlgK)
+ */
+
+/**
+ * Definition for singly-linked list.
+ * struct ListNode {
+ *     int val;
+ *     ListNode *next;
+ *     ListNode(int x) : val(x), next(NULL) {}
+ * };
+ */
+/**
+ * Definition for singly-linked list.
+ * public class ListNode {
+ *     int val;
+ *     ListNode next;
+ *     ListNode(int x) {
+ *         val = x;
+ *         next = null;
+ *     }
+ * }
+ */
+public class Solution {
+    public ListNode mergeKLists_1(List<ListNode> lists) {
+        Comparator<ListNode> comp =  new Comparator<ListNode>(){  
+            public int compare(ListNode a,  ListNode b) {  
+                if(b.val > a.val) {  
+                    return -1;  
+                }else if(b.val < a.val){  
+                    return 1;  
+                } else {  
+                    return 0;  
+                }  
+            }  
+        };
+
+        Queue<ListNode> q =  new PriorityQueue<ListNode>(10,comp);
+        for (int i = 0; i < lists.size(); ++i)
+            if (lists.get(i) != null)
+                q.add(lists.get(i));
+        
+        ListNode dummy = new ListNode(0);
+        ListNode cur = dummy;
+        while (!q.isEmpty()) {
+            ListNode node = q.poll();
+            cur = cur.next = node;
+            if (node.next != null)
+                q.add(node.next);
+        }
+        return dummy.next;
+    }
+    ListNode mergeTwoLists(ListNode l1, ListNode l2) {
+        ListNode head = new ListNode(0);
+        ListNode cur = head;
+        while (l1 != null && l2 != null) {
+            if (l1.val < l2.val) {
+                cur.next = l1;
+                l1 = l1.next;
+            } else {
+                cur.next = l2;
+                l2 = l2.next;
+            }
+            cur = cur.next;
+        }
+        if (l1 != null) cur.next = l1;
+        if (l2 != null) cur.next = l2;
+        return head.next;
+    }
+    public ListNode mergeKLists(List<ListNode> lists) {
+        if(lists.size()==0) return null;
+        int sz = lists.size(), end = sz - 1;
+        while (end > 0) {
+            int begin = 0;
+            while (begin < end) {
+                ListNode node = mergeTwoLists(lists.get(begin), lists.get(end));
+                lists.set(begin, node);
+                ++begin; --end;
+            }
+        }
+        return lists.get(0);
+    }
+}