XML support for Django REST Framework

Full documentation for the project is available at http://jpadilla.github.io/django-rest-framework-xml.

XML support extracted as a third party package directly from the official Django REST Framework implementation. It requires the defusedxml package only because it safeguards against some security issues that were discovered.

Note: XML output provided is an ad-hoc format that isn't formally described. If you have specific XML requirements you'll need to write your own XML parsers/renderers in order to fully control the representation.

• Python (2.7, 3.3, 3.4)
• Django (1.6, 1.7)
• Django REST Framework (2.4.4, 3.0, 3.1)

Install using pip...

$ pip install djangorestframework-xml

REST_FRAMEWORK = {
    'DEFAULT_PARSER_CLASSES': (
        'rest_framework_xml.parsers.XMLParser',
    ),
    'DEFAULT_RENDERER_CLASSES': (
        'rest_framework_xml.renderers.XMLRenderer',
    ),
}

You can also set the renderer and parser used for an individual view, or viewset, using the APIView class based views.

from rest_framework import routers, serializers, viewsets
from rest_framework_xml.parsers import XMLParser
from rest_framework_xml.renderers import XMLRenderer


class UserSerializer(serializers.HyperlinkedModelSerializer):
    class Meta:
        model = User
        fields = ('url', 'username', 'email', 'is_staff')


class UserViewSet(viewsets.ModelViewSet):
    queryset = User.objects.all()
    serializer_class = UserSerializer
    parser_classes = (XMLParser,)
    renderer_classes = (XMLRenderer,)

<?xml version="1.0" encoding="utf-8"?>
<root>
    <list-item>
        <url>http://127.0.0.1:8000/users/1/.xml</url>
        <username>jpadilla</username>
        <email>jpadilla@example.com</email>
        <is_staff>True</is_staff>
    </list-item>
</root>

Full documentation for the project is available at http://jpadilla.github.io/django-rest-framework-xml.

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