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Commit eaa232d

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begeekmyfriendbegeekmyfriend
committed
Improvement
Signed-off-by: begeekmyfriend <begeekmyfriend@gmail.com>
1 parent c40b4b8 commit eaa232d
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6 files changed

+54
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6 files changed

+54
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‎0042_trapping_rain_water/trap_water.c

Copy file name to clipboardExpand all lines: 0042_trapping_rain_water/trap_water.c
+9-13Lines changed: 9 additions & 13 deletions
Original file line numberDiff line numberDiff line change
@@ -35,22 +35,18 @@ static int trap(int* height, int heightSize)
3535
int res = 0;
3636
int l = 0, lmax = 0;
3737
int r = heightSize - 1, rmax = 0;
38+
3839
while (l < r) {
39-
if (height[l] < height[r]) {
40-
/* Only lmax is needed for lmax < rmax here */
41-
if (height[l] > lmax) {
42-
lmax = height[l];
43-
} else {
44-
res += lmax - height[l];
45-
}
40+
/* lmax is the highest in height[0...l] and
41+
* rmax is the highest in height[r...size - 1]
42+
*/
43+
lmax = height[l] > lmax ? height[l] : lmax;
44+
rmax = height[r] > rmax ? height[r] : rmax;
45+
if (lmax < rmax) {
46+
res += lmax - height[l];
4647
l++;
4748
} else {
48-
/* Only rmax is needed for rmax < lmax here */
49-
if (height[r] > rmax) {
50-
rmax = height[r];
51-
} else {
52-
res += rmax - height[r];
53-
}
49+
res += rmax - height[r];
5450
r--;
5551
}
5652
}

‎0042_trapping_rain_water/trap_water.cc

Copy file name to clipboardExpand all lines: 0042_trapping_rain_water/trap_water.cc
+13-18Lines changed: 13 additions & 18 deletions
Original file line numberDiff line numberDiff line change
@@ -9,25 +9,20 @@ class Solution {
99
* water level of the position would be determined by the opposite side.
1010
*/
1111
int res = 0;
12-
int left = 0, left_max = 0;
13-
int right = height.size() - 1, right_max = 0;
14-
while (left < right) {
15-
if (height[left] < height[right]) {
16-
/* Only lmax is needed for lmax < rmax here */
17-
if (height[left] > left_max) {
18-
left_max = height[left];
19-
} else {
20-
res += left_max - height[left];
21-
}
22-
left++;
12+
int l = 0, l_max = 0;
13+
int r = height.size() - 1, r_max = 0;
14+
15+
while (l < r) {
16+
// lmax is the highest in height[0...l] and
17+
// rmax is the highest in height[r...size - 1]
18+
l_max = max(height[l], l_max);
19+
r_max = max(height[r], r_max);
20+
if (l_max < r_max) {
21+
res += l_max - height[l];
22+
l++;
2323
} else {
24-
/* Only rmax is needed for rmax < lmax here */
25-
if (height[right] > right_max) {
26-
right_max = height[right];
27-
} else {
28-
res += right_max - height[right];
29-
}
30-
right--;
24+
res += r_max - height[r];
25+
r--;
3126
}
3227
}
3328

‎0045_jump_game_ii/jump_game.c

Copy file name to clipboardExpand all lines: 0045_jump_game_ii/jump_game.c
+13-10Lines changed: 13 additions & 10 deletions
Original file line numberDiff line numberDiff line change
@@ -1,26 +1,29 @@
11
#include <stdio.h>
22
#include <stdlib.h>
33

4+
45
static inline int max(int a, int b)
56
{
67
return a > b ? a : b;
78
}
89

910
static int jump(int* nums, int numsSize)
1011
{
11-
int i, lo = 0, hi = 0;
12+
int i, right = 0;
1213
int steps = 0;
13-
while (hi < numsSize - 1) {
14-
int right = 0;
15-
for (i = lo; i <= hi; i++) {
16-
/* Assume right > hi for the purpose of the problem */
17-
right = max(i + nums[i], right);
14+
int fartest = 0;
15+
/* 1. Exhaust all the right boundries in the location range of [i...right]
16+
* 2. When the search ends up with i==right, update the right boundry as
17+
* the fartest position.
18+
* 3. When the search ends up with i==right, it records as one jump step */
19+
for (i = 0; i < numsSize; i++) {
20+
fartest = max(i + nums[i], fartest);
21+
if (i == right) {
22+
right = fartest;
23+
steps++;
1824
}
19-
/* [lo, hi] is the next location range */
20-
lo = hi + 1;
21-
hi = right;
22-
steps++;
2325
}
26+
2427
return steps;
2528
}
2629

‎0045_jump_game_ii/jump_game.cc

Copy file name to clipboardExpand all lines: 0045_jump_game_ii/jump_game.cc
+11-10Lines changed: 11 additions & 10 deletions
Original file line numberDiff line numberDiff line change
@@ -6,17 +6,18 @@ class Solution {
66
public:
77
int jump(vector<int>& nums) {
88
int steps = 0;
9-
int lo = 0, hi = 0;
10-
while (hi < nums.size() - 1) {
11-
int right = 0;
12-
for (int i = lo; i <= hi; i++) {
13-
// right > hi for nums[i] > 0
14-
right = max(i + nums[i], right);
9+
int right = 0;
10+
int farthest = 0;
11+
// 1. Exhaust all the right boundries in the location range of [i...right]
12+
// 2. When the search ends up with i==right, update the right boundry as
13+
// the fartest position.
14+
// 3. When the search ends up with i==right, it records as one jump step */
15+
for (int i = 0; i < nums.size() - 1; i++) {
16+
fartest = max(i + nums[i], fartest);
17+
for (i == right) {
18+
right = fartest;
19+
steps++;
1520
}
16-
// [lo, hi] is the next location range
17-
lo = hi + 1;
18-
hi = right;
19-
steps++;
2021
}
2122

2223
return steps;

‎0198_house_robber/robber.c

Copy file name to clipboardExpand all lines: 0198_house_robber/robber.c
+4-2Lines changed: 4 additions & 2 deletions
Original file line numberDiff line numberDiff line change
@@ -14,10 +14,12 @@ static int rob(int* nums, int numsSize)
1414
int untaken = 0;
1515
/* Record max profits of nums[0...i] respectively */
1616
for (i = 0; i < numsSize; i++) {
17-
int tmp_taken = taken;
17+
int last_taken = taken;
1818
/* Taken or untaken nums[i] */
19+
/* last taken + nums[i] */
1920
taken = untaken + nums[i];
20-
untaken = max(tmp_taken, untaken);
21+
/* max(last untaken, last taken) */
22+
untaken = max(last_taken, untaken);
2123
}
2224

2325
return max(taken, untaken);

‎0198_house_robber/robber.cc

Copy file name to clipboardExpand all lines: 0198_house_robber/robber.cc
+4-2Lines changed: 4 additions & 2 deletions
Original file line numberDiff line numberDiff line change
@@ -8,9 +8,11 @@ class Solution {
88
int taken = 0;
99
int untaken = 0;
1010
for (int i = 0; i < nums.size(); i++) {
11-
int tmp_taken = taken;
11+
int last_taken = taken;
12+
/* last untaken + nums[i]*/
1213
taken = untaken + nums[i];
13-
untaken = max(untaken, tmp_taken);
14+
/* max(last untaken, last taken) */
15+
untaken = max(untaken, last_taken);
1416
}
1517
return max(taken, untaken);
1618
}

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