/**

• AtomicMarkableReference则是将一个boolean值作是否有更改的标记，本质就是它的版本号只有两个，true和false，

• 修改的时候在这两个版本号之间来回切换，这样做并不能解决ABA的问题，只是会降低ABA问题发生的几率而已

• @author : mazh

• @Date : 2020/1/17 14:41
  */
  public class SolveABAByAtomicMarkableReference {
  private static AtomicMarkableReference atomicMarkableReference = new AtomicMarkableReference(100,false);

  public static void main(String[] args) {

   Thread refT1 = new Thread(() -> {
       try {
           TimeUnit.SECONDS.sleep(1);
       } catch (InterruptedException e) {
           e.printStackTrace();
       }
       atomicMarkableReference.compareAndSet(100, 101, atomicMarkableReference.isMarked(), !atomicMarkableReference.isMarked());
       atomicMarkableReference.compareAndSet(101, 100, atomicMarkableReference.isMarked(), !atomicMarkableReference.isMarked());
   });
  
   Thread refT2 = new Thread(() -> {
       boolean marked = atomicMarkableReference.isMarked();
       try {
           TimeUnit.SECONDS.sleep(2);
       } catch (InterruptedException e) {
           e.printStackTrace();
       }
       boolean c3 = atomicMarkableReference.compareAndSet(100, 101, marked, !marked);
       System.out.println(c3); // 返回true,实际应该返回false
   });
  
   refT1.start();
   refT2.start();
  

  }
  }

个人理解是这样，不知是否正确？