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Commit 37f9d34

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Fastest way to find prime number
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/*
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written by Pankaj Kumar.
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country:-INDIA
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*/
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#include <bits/stdc++.h>
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#include <ext/pb_ds/assoc_container.hpp>
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#include <ext/pb_ds/tree_policy.hpp>
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using namespace std;
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using namespace __gnu_pbds;
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typedef long long ll ;
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typedef vector<ll> vl;
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#define speed cin.tie(0);cout.tie(0);ios_base::sync_with_stdio(0);
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// define values.
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// #define mod 1000000007
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#define phi 1.618
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/* Abbrevations */
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#define ff first
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#define ss second
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#define mp make_pair
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#define line cout<<endl;
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#define pb push_back
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#define Endl "\n"
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// loops
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#define forin(arr,n) for(ll i=0;i<n;i++) cin>>arr[i];
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// Some print
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#define no cout<<"NO"<<endl;
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#define yes cout<<"YES"<<endl;
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#define cc ll test;cin>>test;while(test--)
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// sort
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#define all(V) (V).begin(),(V).end()
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#define srt(V) sort(all(V))
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#define srtGreat(V) sort(all(V),greater<ll>())
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#define printv(v) for(ll i=0;i<ll(v.size());i++){cout<<v[i]<<" ";} line;
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// some extra
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#define sz(V) ll(V.size())
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/* ONLINE JUDGE */
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// #ifdef ONLINE_JUDGE
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// freopen("input.txt", "r", stdin);freopen("output.txt", "w", stdout);
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// #endif
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// function
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ll power(ll x,ll y,ll mod)
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{
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ll res=1;
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// x=x%mod;
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while(y>0)
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{
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if(y%2==1)
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{
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res*=x;
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// res=res%mod;
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}
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y/=2; x*=x; // x=x%mod;
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}
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return res;
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}
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// datatype definination
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#define ordered_set tree<ll,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update>
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/* ascii value
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A=65,Z=90,a=97,z=122
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*/
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/* -----------------------------------------------------------------------------------*/
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ll solve()
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{
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cout<<"This is to print all prime number smaller of equal to given number."<<endl;
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ll n;
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cin>>n;
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vector<bool> prime(n+1,true);
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for(ll i=2;i*i<=n;i++)
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{
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if(prime[i])
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{
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for(ll j=i*i;j<n;j+=i)
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prime[j]=false;
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}
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}
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cout<<"List of all prime number is: ";
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for(ll i=2;i<=n;i++)
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{
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if(prime[i])
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cout<<i<<" ";
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}
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line;
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return 0;
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}
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int main()
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{
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speed;
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// freopen("input.txt","r",stdin);
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// freopen("output.txt","w",stdout);
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solve();
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}
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/* stuff you should look before submission
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* int overflow
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* special test case (n=0||n=1||n=2)
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* don't get stuck on one approach if you get wrong answer
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*/

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