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#!/usr/bin/env python
from __future__ import division
import random
'''
Leetcode: Permutations
Given a collection of numbers, return all possible permutations.
For example,
[1,2,3] have the following permutations:
[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], and [3,2,1].
'''
'''
Leetcode: Permutations II
Given a collection of numbers that might contain duplicates, return all possible unique permutations.
For example,
[1,1,2] have the following unique permutations:
[1,1,2], [1,2,1], and [2,1,1]
'''
def gen_permu(L):
n = len(L)
if n == 0: yield []
elif n == 1: yield L
else:
checked = set() # cache digit that has been put at this position
for i in range(n):
if L[i] in checked: continue
checked.add(L[i])
for p in gen_permu(L[:i] + L[i+1:]):
yield [L[i]] + p
def permu(L):
counter = 0
for p in gen_permu(L):
print p
counter += 1
print 'Total:', counter
if __name__ == '__main__':
permu([1,2,3,4])
print
permu([1,1,2,3])
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