Jump to content

Weyl's theorem on complete reducibility

From Wikipedia, the free encyclopedia

In algebra, Weyl's theorem on complete reducibility is a fundamental result in the theory of Lie algebra representations (specifically in the representation theory of semisimple Lie algebras). Let {\displaystyle {\mathfrak {g}}} be a semisimple Lie algebra over a field of characteristic zero. The theorem states that every finite-dimensional module over {\displaystyle {\mathfrak {g}}} is semisimple as a module (i.e., a direct sum of simple modules.)[1]

The enveloping algebra is semisimple

[edit]

Weyl's theorem implies (in fact is equivalent to) that the enveloping algebra of a finite-dimensional representation is a semisimple ring in the following way.

Given a finite-dimensional Lie algebra representation {\displaystyle \pi :{\mathfrak {g}}\to {\mathfrak {gl}}(V)}, let {\displaystyle A\subset \operatorname {End} (V)} be the associative subalgebra of the endomorphism algebra of V generated by {\displaystyle \pi ({\mathfrak {g}})}. The ring A is called the enveloping algebra of {\displaystyle \pi }. If {\displaystyle \pi } is semisimple, then A is semisimple.[2] (Proof: Since A is a finite-dimensional algebra, it is an Artinian ring; in particular, the Jacobson radical J is nilpotent. If V is simple, then {\displaystyle JV\subset V} implies that {\displaystyle JV=0}. In general, J kills each simple submodule of V; in particular, J kills V and so J is zero.) Conversely, if A is semisimple, then V is a semisimple A-module; i.e., semisimple as a {\displaystyle {\mathfrak {g}}}-module. (Note that a module over a semisimple ring is semisimple since a module is a quotient of a free module and "semisimple" is preserved under the free and quotient constructions.)

Application: preservation of Jordan decomposition

[edit]

Here is a typical application.[3]

PropositionLet {\displaystyle {\mathfrak {g}}} be a semisimple finite-dimensional Lie algebra over a field of characteristic zero and {\displaystyle x} an element of {\displaystyle {\mathfrak {g}}}.[a]

  1. There exists a unique pair of elements {\displaystyle x_{s},x_{n}} in {\displaystyle {\mathfrak {g}}} such that {\displaystyle x=x_{s}+x_{n}}, {\displaystyle \operatorname {ad} (x_{s})} is semisimple, {\displaystyle \operatorname {ad} (x_{n})} is nilpotent and {\displaystyle [x_{s},x_{n}]=0}.
  2. If {\displaystyle \pi :{\mathfrak {g}}\to {\mathfrak {gl}}(V)} is a finite-dimensional representation, then {\displaystyle \pi (x)_{s}=\pi (x_{s})} and {\displaystyle \pi (x)_{n}=\pi (x_{n})}, where {\displaystyle \pi (x)_{s},\pi (x)_{n}} denote the Jordan decomposition of the semisimple and nilpotent parts of the endomorphism {\displaystyle \pi (x)}.

In short, the semisimple and nilpotent parts of an element of {\displaystyle {\mathfrak {g}}} are well-defined and are determined independent of a faithful finite-dimensional representation.

Proof: First we prove the special case of (i) and (ii) when {\displaystyle \pi } is the inclusion; i.e., {\displaystyle {\mathfrak {g}}} is a subalgebra of {\displaystyle {\mathfrak {gl}}_{n}={\mathfrak {gl}}(V)}. Let {\displaystyle x=S+N} be the Jordan decomposition of the endomorphism {\displaystyle x}, where {\displaystyle S,N} are semisimple and nilpotent endomorphisms in {\displaystyle {\mathfrak {gl}}_{n}}. Now, {\displaystyle \operatorname {ad} _{{\mathfrak {gl}}_{n}}(x)} also has the Jordan decomposition, which can be shown (see Jordan–Chevalley decomposition) to respect the above Jordan decomposition; i.e., {\displaystyle \operatorname {ad} _{{\mathfrak {gl}}_{n}}(S),\operatorname {ad} _{{\mathfrak {gl}}_{n}}(N)} are the semisimple and nilpotent parts of {\displaystyle \operatorname {ad} _{{\mathfrak {gl}}_{n}}(x)}. Since {\displaystyle \operatorname {ad} _{{\mathfrak {gl}}_{n}}(S),\operatorname {ad} _{{\mathfrak {gl}}_{n}}(N)} are polynomials in {\displaystyle \operatorname {ad} _{{\mathfrak {gl}}_{n}}(x)} then, we see {\displaystyle \operatorname {ad} _{{\mathfrak {gl}}_{n}}(S),\operatorname {ad} _{{\mathfrak {gl}}_{n}}(N):{\mathfrak {g}}\to {\mathfrak {g}}}. Thus, they are derivations of {\displaystyle {\mathfrak {g}}}. Since {\displaystyle {\mathfrak {g}}} is semisimple, we can find elements {\displaystyle s,n} in {\displaystyle {\mathfrak {g}}} such that {\displaystyle [y,S]=[y,s],y\in {\mathfrak {g}}} and similarly for {\displaystyle n}. Now, let A be the enveloping algebra of {\displaystyle {\mathfrak {g}}}; i.e., the subalgebra of the endomorphism algebra of V generated by {\displaystyle {\mathfrak {g}}}. As noted above, A has zero Jacobson radical. Since {\displaystyle [y,N-n]=0}, we see that {\displaystyle N-n} is a nilpotent element in the center of A. But, in general, a central nilpotent belongs to the Jacobson radical; hence, {\displaystyle N=n} and thus also {\displaystyle S=s}. This proves the special case.

In general, {\displaystyle \pi (x)} is semisimple (resp. nilpotent) when {\displaystyle \operatorname {ad} (x)} is semisimple (resp. nilpotent).[clarification needed] This immediately gives (i) and (ii). {\displaystyle \square }

Proofs

[edit]

Analytic proof

[edit]

Weyl's original proof (for complex semisimple Lie algebras) was analytic in nature: it famously used the unitarian trick. Specifically, one can show that every complex semisimple Lie algebra {\displaystyle {\mathfrak {g}}} is the complexification of the Lie algebra of a simply connected compact Lie group {\displaystyle K}.[4] (If, for example, {\displaystyle {\mathfrak {g}}=\mathrm {sl} (n;\mathbb {C} )}, then {\displaystyle K=\mathrm {SU} (n)}.) Given a representation {\displaystyle \pi } of {\displaystyle {\mathfrak {g}}} on a vector space {\displaystyle V,} one can first restrict {\displaystyle \pi } to the Lie algebra {\displaystyle {\mathfrak {k}}} of {\displaystyle K}. Then, since {\displaystyle K} is simply connected,[5] there is an associated representation {\displaystyle \Pi } of {\displaystyle K}. Integration over {\displaystyle K} produces an inner product on {\displaystyle V} for which {\displaystyle \Pi } is unitary.[6] Complete reducibility of {\displaystyle \Pi } is then immediate and elementary arguments show that the original representation {\displaystyle \pi } of {\displaystyle {\mathfrak {g}}} is also completely reducible.

Algebraic proof 1

[edit]

Let {\displaystyle (\pi ,V)} be a finite-dimensional representation of a Lie algebra {\displaystyle {\mathfrak {g}}} over a field of characteristic zero. The theorem is an easy consequence of Whitehead's lemma, which says {\displaystyle V\to \operatorname {Der} ({\mathfrak {g}},V),v\mapsto \cdot v} is surjective, where a linear map {\displaystyle f:{\mathfrak {g}}\to V} is a derivation if {\displaystyle f([x,y])=x\cdot f(y)-y\cdot f(x)}. The proof is essentially due to Whitehead.[7]

Let {\displaystyle W\subset V} be a subrepresentation. Consider the vector subspace {\displaystyle L_{W}\subset \operatorname {End} (V)} that consists of all linear maps {\displaystyle t:V\to V} such that {\displaystyle t(V)\subset W} and {\displaystyle t(W)=0}. It has a structure of a {\displaystyle {\mathfrak {g}}}-module given by: for {\displaystyle x\in {\mathfrak {g}},t\in L_{W}},

{\displaystyle x\cdot t=[\pi (x),t]}.

Now, pick some projection {\displaystyle p:V\to V} onto W and consider {\displaystyle f:{\mathfrak {g}}\to L_{W}} given by {\displaystyle f(x)=[p,\pi (x)]}. Since {\displaystyle f} is a derivation, by Whitehead's lemma, we can write {\displaystyle f(x)=x\cdot t} for some {\displaystyle t\in L_{W}}. We then have {\displaystyle [\pi (x),p+t]=0,x\in {\mathfrak {g}}}; that is to say {\displaystyle p+t} is {\displaystyle {\mathfrak {g}}}-linear. Also, as t kills {\displaystyle W}, {\displaystyle p+t} is an idempotent such that {\displaystyle (p+t)(V)=W}. The kernel of {\displaystyle p+t} is then a complementary representation to {\displaystyle W}. {\displaystyle \square }

Algebraic proof 2

[edit]

Whitehead's lemma is typically proved by means of the quadratic Casimir element of the universal enveloping algebra,[8] and there is also a proof of the theorem that uses the Casimir element directly instead of Whitehead's lemma.

Since the quadratic Casimir element {\displaystyle C} is in the center of the universal enveloping algebra, Schur's lemma tells us that {\displaystyle C} acts as multiple {\displaystyle c_{\lambda }} of the identity in the irreducible representation of {\displaystyle {\mathfrak {g}}} with highest weight {\displaystyle \lambda }. A key point is to establish that {\displaystyle c_{\lambda }} is nonzero whenever the representation is nontrivial. This can be done by a general argument [9] or by the explicit formula for {\displaystyle c_{\lambda }}.

Consider a very special case of the theorem on complete reducibility: the case where a representation {\displaystyle V} contains a nontrivial, irreducible, invariant subspace {\displaystyle W} of codimension one. Let {\displaystyle C_{V}} denote the action of {\displaystyle C} on {\displaystyle V}. Since {\displaystyle V} is not irreducible, {\displaystyle C_{V}} is not necessarily a multiple of the identity, but it is a self-intertwining operator for {\displaystyle V}. Then the restriction of {\displaystyle C_{V}} to {\displaystyle W} is a nonzero multiple of the identity. But since the quotient {\displaystyle V/W} is a one dimensional—and therefore trivial—representation of {\displaystyle {\mathfrak {g}}}, the action of {\displaystyle C} on the quotient is trivial. It then easily follows that {\displaystyle C_{V}} must have a nonzero kernel—and the kernel is an invariant subspace, since {\displaystyle C_{V}} is a self-intertwiner. The kernel is then a one-dimensional invariant subspace, whose intersection with {\displaystyle W} is zero. Thus, {\displaystyle \mathrm {ker} (V_{C})} is an invariant complement to {\displaystyle W}, so that {\displaystyle V} decomposes as a direct sum of irreducible subspaces:

{\displaystyle V=W\oplus \mathrm {ker} (C_{V})}.

Although this establishes only a very special case of the desired result, this step is actually the critical one in the general argument.

Algebraic proof 3

[edit]

The theorem can be deduced from the theory of Verma modules, which characterizes a simple module as a quotient of a Verma module by a maximal submodule.[10] This approach has an advantage that it can be used to weaken the finite-dimensionality assumptions (on algebra and representation).

Let {\displaystyle V} be a finite-dimensional representation of a finite-dimensional semisimple Lie algebra {\displaystyle {\mathfrak {g}}} over an algebraically closed field of characteristic zero. Let {\displaystyle {\mathfrak {b}}={\mathfrak {h}}\oplus {\mathfrak {n}}_{+}\subset {\mathfrak {g}}} be the Borel subalgebra determined by a choice of a Cartan subalgebra and positive roots. Let {\displaystyle V^{0}=\{v\in V|{\mathfrak {n}}_{+}(v)=0\}}. Then {\displaystyle V^{0}} is an {\displaystyle {\mathfrak {h}}}-module and thus has the {\displaystyle {\mathfrak {h}}}-weight space decomposition:

{\displaystyle V^{0}=\bigoplus _{\lambda \in L}V_{\lambda }^{0}}

where {\displaystyle L\subset {\mathfrak {h}}^{*}}. For each {\displaystyle \lambda \in L}, pick {\displaystyle 0\neq v_{\lambda }\in V_{\lambda }} and {\displaystyle V^{\lambda }\subset V} the {\displaystyle {\mathfrak {g}}}-submodule generated by {\displaystyle v_{\lambda }} and {\displaystyle V'\subset V} the {\displaystyle {\mathfrak {g}}}-submodule generated by {\displaystyle V^{0}}. We claim: {\displaystyle V=V'}. Suppose {\displaystyle V\neq V'}. By Lie's theorem, there exists a {\displaystyle {\mathfrak {b}}}-weight vector in {\displaystyle V/V'}; thus, we can find an {\displaystyle {\mathfrak {h}}}-weight vector {\displaystyle v} such that {\displaystyle 0\neq e_{i}(v)\in V'} for some {\displaystyle e_{i}} among the Chevalley generators. Now, {\displaystyle e_{i}(v)} has weight {\displaystyle \mu +\alpha _{i}}. Since {\displaystyle L} is partially ordered, there is a {\displaystyle \lambda \in L} such that {\displaystyle \lambda \geq \mu +\alpha _{i}}; i.e., {\displaystyle \lambda >\mu }. But this is a contradiction since {\displaystyle \lambda ,\mu } are both primitive weights (it is known that the primitive weights are incomparable.[clarification needed]). Similarly, each {\displaystyle V^{\lambda }} is simple as a {\displaystyle {\mathfrak {g}}}-module. Indeed, if it is not simple, then, for some {\displaystyle \mu <\lambda }, {\displaystyle V_{\mu }^{0}} contains some nonzero vector that is not a highest-weight vector; again a contradiction.[clarification needed] {\displaystyle \square }

Algebraic proof 4

[edit]

There is also a quick homological algebra proof; see Weibel's homological algebra book.

[edit]

References

[edit]
  1. ^ Editorial note: this fact is usually stated for a field of characteristic zero, but the proof needs only that the base field be perfect.
  1. ^ Hall 2015 Theorem 10.9
  2. ^ Jacobson 1979, Ch. II, § 5, Theorem 10.
  3. ^ Jacobson 1979, Ch. III, § 11, Theorem 17.
  4. ^ Knapp 2002 Theorem 6.11
  5. ^ Hall 2015 Theorem 5.10
  6. ^ Hall 2015 Theorem 4.28
  7. ^ Jacobson 1979, Ch. III, § 7.
  8. ^ Hall 2015 Section 10.3
  9. ^ Humphreys 1973 Section 6.2
  10. ^ Kac 1990, Lemma 9.5.
  • Hall, Brian C. (2015). Lie Groups, Lie Algebras, and Representations: An Elementary Introduction. Graduate Texts in Mathematics. Vol. 222 (2nd ed.). Springer. ISBN 978-3319134666.
  • Humphreys, James E. (1973). Introduction to Lie Algebras and Representation Theory. Graduate Texts in Mathematics. Vol. 9 (Second printing, revised ed.). New York: Springer-Verlag. ISBN 0-387-90053-5.
  • Jacobson, Nathan (1979). Lie algebras. New York: Dover Publications, Inc. ISBN 0-486-63832-4. Republication of the 1962 original.
  • Kac, Victor (1990). Infinite dimensional Lie algebras (3rd ed.). Cambridge University Press. ISBN 0-521-46693-8.
  • Knapp, Anthony W. (2002), Lie Groups Beyond an Introduction, Progress in Mathematics, vol. 140 (2nd ed.), Boston: Birkhäuser, ISBN 0-8176-4259-5
  • Weibel, Charles A. (1995). An Introduction to Homological Algebra. Cambridge University Press.
Weyl's theorem on complete reducibility
Morty Proxy This is a proxified and sanitized view of the page, visit original site.