std::chrono::year::is_leap
From cppreference.com
constexpr bool is_leap() const noexcept;
|
(since C++20) | |
Determines if *this represents a leap year in the proleptic Gregorian calendar.
*this represents a leap year if the stored year value
- is divisible by 4 and not divisible by 100; or
- is divisible by 400.
Return value
true if *this represents a leap year, otherwise false.
Example
Run this code
#include <chrono>
#include <iostream>
int main()
{
using namespace std::chrono_literals;
for (const std::chrono::year y : {2020y, 2021y, 2000y, 3000y})
{
if (const int iy{static_cast<int>(y)}; y.is_leap())
std::cout << iy << " is a leap year because it is divisible by "
<< (iy % 400 == 0 ? "400\n" : "4 and not divisible by 100\n");
else
std::cout << iy << " is not a leap year\n";
}
}
Output:
2020 is a leap year because it is divisible by 4 and not divisible by 100
2021 is not a leap year
2000 is a leap year because it is divisible by 400
3000 is not a leap year