Java programming.

Question -

You are given an array a with N integers and an integer K. Output the smallest number in array which occurs exactly K times in an array. There will always be a number that is occurring K times.


Sample Input
5
2 2 1 3 1
2

Sample Output
1

MY code - import java.io.*; import java.util.Scanner; public class Smallno {    public static void main(String[] args) throws IOException {        Scanner sc = new Scanner(System.in);        int N, K, i;        N = sc.nextInt();        int arr [] = new int[N];        int freq [] = new int[10];                for (i=0; i<N; i++){            arr[i] = sc.nextInt();        }                K = sc.nextInt();                for(i=0; i<N; i++){            freq[arr[i]]++;        }                for(i=0; i<10; i++){            if(freq[i] == K){                System.out.println(i);                break;            }        }    } }

why does my code says runtime error?

Please post the full stacktrace

Welcome to the Ranch!

I formatted your code for you. Doesn't that make it much easier to see what is going on?

Welcome again

Please always put spaces between (non‑unary) operators and operands: not for (i=0; i<N; i++) ... please but for (i = 0; i < N; i++) ... No space in i++ however. Don't put constants in the for header. Write myArray.length instead. >
I like your counting technique, but what makes you think there will not bemore than ten different values?